(x/3-5)^2=16

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Solution for (x/3-5)^2=16 equation: 


x in (-oo:+oo)

(x/3-5)^2 = 16 // - 16

(x/3-5)^2-16 = 0

(1/3*x-5)^2-16 = 0

(1/3*x-5)^2-16 = 0

1/9*x^2-10/3*x+9 = 0

1/9*x^2-10/3*x+9 = 0

1/9*x^2-10/3*x+9 = 0

DELTA = (-10/3)^2-(1/9*4*9)

DELTA = 64/9

DELTA > 0

x = ((64/9)^(1/2)+10/3)/(1/9*2) or x = (10/3-(64/9)^(1/2))/(1/9*2)

x = 27 or x = 3

(x-3)*(x-27) = 0

(x-3)*(x-27) = 0

( x-27 )

x-27 = 0 // + 27

x = 27

( x-3 )

x-3 = 0 // + 3

x = 3

x in { 27, 3 }

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